Count()
Same as CountCS: How many times the given substring occurs.
also written: NumberOfOccurrences
Basic examples (2)
oAB = new stzString("ab")
big = new stzString( oAB.Repeated(1000000) )
# NumberOfOccurrences('a') is 1,000,000 (> 65536)
? big.NumberOfOccurrences("a")
# FindAll('a') returns all 1,000,000 positions
? len(big.FindAll("a"))
# NumberOfOccurrences('ab') is 1,000,000
? big.NumberOfOccurrences("ab")1000000 1000000 1000000
run on 2026-10-02 04:24 inside the library at commit 0e72e2e2c; taken from 999_engine_string_millions_narrated.ring(opens in a new tab)
oAB = new stzString("ab")
big = new stzString( oAB.Repeated(1000000) )
oE = new stzString("😀🎉")
e = new stzString( oE.Repeated(50000) )
# NumberOfChars is 100,000 codepoints
? e.NumberOfChars()
# NumberOfOccurrences('😀') is 50,000
? e.NumberOfOccurrences("😀")
# Reversed keeps 100,000 codepoints
? StzLen(e.Reversed())100000 50000 100000
run on 2026-10-02 04:24 inside the library at commit 0e72e2e2c; taken from 999_engine_string_millions_narrated.ring(opens in a new tab)
Scope (3)
oAB = new stzString("ab")
big = new stzString( oAB.Repeated(1000000) )
oRep = new stzString( oAB.Repeated(500000) ) # 1,000,000 chars
oRep.Replace("a", "X")
# after Replace, 'a' is gone
? oRep.NumberOfOccurrences("a")
# after Replace, 'X' is 500,000
? oRep.NumberOfOccurrences("X")
# 'b' is untouched at 500,000
? oRep.NumberOfOccurrences("b")0 500000 500000
run on 2026-10-02 04:24 inside the library at commit 0e72e2e2c; taken from 999_engine_string_millions_narrated.ring(opens in a new tab)
oAB = new stzString("ab")
big = new stzString( oAB.Repeated(1000000) )
oUp = new stzString( big.Uppercased() )
# Uppercased keeps full 2,000,000 length
? oUp.NumberOfChars()
# Uppercased head is 'ABAB'
? oUp.Section(1, 4)
# Uppercased has 1,000,000 'A'
? oUp.NumberOfOccurrences("A")
# Uppercased has zero 'a'
? oUp.NumberOfOccurrences("a")2000000 ABAB 1000000 0
run on 2026-10-02 04:24 inside the library at commit 0e72e2e2c; taken from 999_engine_string_millions_narrated.ring(opens in a new tab)
oAB = new stzString("ab")
big = new stzString( oAB.Repeated(1000000) )
oAr = new stzString("سلام")
ar = new stzString( oAr.Repeated(100000) )
# NumberOfChars is 400,000 codepoints
? ar.NumberOfChars()
# NumberOfOccurrences('سلام') is 100,000
? ar.NumberOfOccurrences("سلام")
# Contains inner 'لا' is TRUE
? ar.Contains("لا")
# Reversed keeps 400,000 codepoints
? StzLen(ar.Reversed())400000 100000 1 400000
run on 2026-10-02 04:24 inside the library at commit 0e72e2e2c; taken from 999_engine_string_millions_narrated.ring(opens in a new tab)
The extensions of this method
Each extension, and whether it exists for this method; an extension that exists combines with the others (FindSTCS).
Every example is a test file of the library, run inside the library for this page; only those whose output kept every promise their file wrote are shown.
See also
- The class stzString
- The area's reference: String
- The other methods in these examples: stzString.Contains · stzString.Find · stzString.NumberOfChars · stzString.Replace · stzString.Reversed · stzString.Section
- How-to: Count how many times a substring appears

